{"id":3335,"date":"2026-05-14T03:55:05","date_gmt":"2026-05-14T03:55:05","guid":{"rendered":"https:\/\/sprocket-chain.net\/?p=3335"},"modified":"2026-05-14T03:55:05","modified_gmt":"2026-05-14T03:55:05","slug":"how-to-calculate-sprocket-tooth-count-for-any-speed-ratio","status":"publish","type":"post","link":"https:\/\/sprocket-chain.net\/tr\/how-to-calculate-sprocket-tooth-count-for-any-speed-ratio\/","title":{"rendered":"Herhangi Bir H\u0131z Oran\u0131 \u0130\u00e7in Di\u015fli Say\u0131s\u0131 Nas\u0131l Hesaplan\u0131r?"},"content":{"rendered":"
\n

<\/p>\n

<\/p>\n
<\/div>\n
<\/div>\n

<\/p>\n

<\/div>\n
<\/div>\n
\n
ben = N2 \/ N1 \u2192 n2 = n1 \u00d7 (N1 \/ N2)<\/div>\n

Herhangi Bir H\u0131z Oran\u0131 \u0130\u00e7in Di\u015fli Say\u0131s\u0131 Nas\u0131l Hesaplan\u0131r?<\/h1>\n

Di\u015fli \u00e7ark di\u015f say\u0131s\u0131n\u0131, gerekli h\u0131z oran\u0131, \u015faft h\u0131z\u0131 veya tork \u00e7\u0131k\u0131\u015f\u0131ndan geriye do\u011fru hesaplayarak se\u00e7in ve ard\u0131ndan bu say\u0131lar\u0131, tahrik sisteminin hizmette g\u00fcvenilir bir \u015fekilde \u00e7al\u0131\u015f\u0131p \u00e7al\u0131\u015fmayaca\u011f\u0131n\u0131 belirleyen m\u00fchendislik k\u0131s\u0131tlamalar\u0131yla kar\u015f\u0131la\u015ft\u0131r\u0131n.<\/p>\n

M\u00fchendislerimizin di\u015f say\u0131m\u0131 hesaplaman\u0131z\u0131 do\u011frulamas\u0131na izin verin.<\/a><\/p>\n<\/div>\n<\/div>\n

\n

<\/p>\n

2024 y\u0131l\u0131nda yeni bir konvey\u00f6r tahrik sistemi tasarlayan bir makine m\u00fchendisi, vidal\u0131 konvey\u00f6r i\u00e7in 1450 RPM'lik bir motorun \u015faft h\u0131z\u0131n\u0131 185 RPM'ye d\u00fc\u015f\u00fcrmesi gerekiyordu; bu da yakla\u015f\u0131k 7,8:1 oran\u0131na denk geliyordu. Tam olarak 7,82:1 oran\u0131n\u0131 elde etmek i\u00e7in 17 di\u015fli tahrik di\u015flisi ve 133 di\u015fli tahrik edilen di\u015fli \u00e7ark\u0131 olan #80 zincirini se\u00e7ti. Hesaplama do\u011fruydu. Ancak tahrik sistemi, ilk hafta i\u00e7inde tasar\u0131m h\u0131z\u0131nda gerekli \u00e7\u0131k\u0131\u015f\u0131 sa\u011flayamad\u0131. 133 di\u015fli tahrik edilen di\u015fli \u00e7ark\u0131n\u0131n d\u0131\u015f \u00e7ap\u0131 yakla\u015f\u0131k 1082 mm idi; bu da mevcut montaj bo\u015flu\u011funu 220 mm a\u015f\u0131yordu. Oran do\u011fruydu, ancak fiziksel boyut uygun de\u011fildi. Tahrik sistemi, orijinal imalat maliyetinin iki kat\u0131na mal olan, ara \u015faftl\u0131 iki kademeli bir d\u00fczenleme olarak yeniden in\u015fa edilmek zorunda kald\u0131.<\/p>\n

Di\u015fli \u00e7ark di\u015f say\u0131s\u0131n\u0131 do\u011fru hesaplamak, oran denklemini \u00e7\u00f6zmekten daha fazlas\u0131n\u0131 gerektirir. Bu, bir di\u015f say\u0131s\u0131 k\u00fcmesinin ger\u00e7ekten kullan\u0131labilir olup olmad\u0131\u011f\u0131n\u0131 belirleyen be\u015f k\u0131s\u0131tlamay\u0131 ele almay\u0131 gerektirir: minimum tahrik eden di\u015f say\u0131s\u0131, maksimum tahrik edilen di\u015fli \u00e7ark \u00e7ap\u0131, sar\u0131lma a\u00e7\u0131s\u0131, merkez mesafesi ve e\u015fit a\u015f\u0131nma da\u011f\u0131l\u0131m\u0131 i\u00e7in gerekli olan avlanma di\u015fi say\u0131s\u0131. Bu k\u0131lavuz, en yayg\u0131n hesaplama senaryolar\u0131 i\u00e7in \u00f6rneklerle birlikte bu be\u015f k\u0131s\u0131tlaman\u0131n tamam\u0131n\u0131 kapsamaktad\u0131r.<\/p>\n

\"\u015fanz\u0131man<\/p>\n

Temel Oran Form\u00fcl\u00fc ve Sa\u011flad\u0131\u011f\u0131 Faydalar<\/h2>\n
\n
D\u00f6rt Zincir Tahrik Denklemi<\/div>\n
\n
\n
i = N2 \/ N1<\/div>\n
Aktar\u0131m oran\u0131. N2 = tahrik edilen (daha b\u00fcy\u00fck) di\u015fli. N1 = tahrik eden (daha k\u00fc\u00e7\u00fck) di\u015fli.<\/div>\n<\/div>\n
\n
n2 = n1 \u00d7 (N1\/N2)<\/div>\n
\u00c7\u0131k\u0131\u015f mili h\u0131z\u0131 (devir\/dakika). n1 = tahrik h\u0131z\u0131. Sonu\u00e7: \u00e7\u0131k\u0131\u015f h\u0131z\u0131.<\/div>\n<\/div>\n
\n
T2 = T1 \u00d7 i \u00d7 \u03b7<\/div>\n
\u00c7\u0131k\u0131\u015f torku. T1 = giri\u015f torku (Nm). \u03b7 = tahrik verimlili\u011fi (0,97\u20130,985).<\/div>\n<\/div>\n
\n
PD = p \/ sin(180\u00b0\/N)<\/div>\n
Di\u015fli \u00e7emberinin \u00e7ap\u0131. p = zincir ad\u0131m\u0131 (mm). N = di\u015f say\u0131s\u0131. Di\u015fli \u00e7ark\u0131n \u00e7al\u0131\u015fma alan\u0131n\u0131 kontrol etmek i\u00e7in kullan\u0131l\u0131r.<\/div>\n<\/div>\n<\/div>\n<\/div>\n

Oran denklemi, di\u015f say\u0131lar\u0131 aras\u0131ndaki ili\u015fkiyi g\u00f6sterir; ancak hangi spesifik di\u015f say\u0131lar\u0131n\u0131n kullan\u0131laca\u011f\u0131n\u0131 s\u00f6ylemez. 4:1 oran\u0131, 17:68, 18:72, 19:76, 21:84 veya d\u00fczinelerce ba\u015fka kombinasyonla elde edilebilir. Her kombinasyon, tahrik edilen di\u015fli i\u00e7in biraz farkl\u0131 bir ad\u0131m dairesi \u00e7ap\u0131, biraz farkl\u0131 bir zincir uzunlu\u011fu ve tahrik di\u015flisinde temas eden farkl\u0131 say\u0131da di\u015f \u00fcretir. A\u015fa\u011f\u0131daki k\u0131s\u0131tlamalar, belirli bir uygulama i\u00e7in hangi kombinasyonlar\u0131n ger\u00e7ekten kullan\u0131labilir oldu\u011funu belirler.<\/p>\n

<\/p>\n

Ge\u00e7erli Di\u015f Say\u0131s\u0131 Kombinasyonlar\u0131n\u0131 Belirleyen Be\u015f K\u0131s\u0131tlama<\/h2>\n

<\/p>\n

\n
\n
1<\/div>\n
Minimum tahrik di\u015fi say\u0131s\u0131: 17T (ANSI B29.1)<\/div>\n<\/div>\n
\n

ANSI B29.1 standard\u0131, sorunsuz zincir tahrik \u00e7al\u0131\u015fmas\u0131 i\u00e7in pratik minimum olarak 17 di\u015f belirler. 17 di\u015fin alt\u0131nda, poligon etkisi h\u0131z varyasyonu \u00b11,7%'yi a\u015far; bu, tahrik edilen \u015fafttaki titre\u015fimin \u00f6l\u00e7\u00fclebilir hale geldi\u011fi e\u015fiktir. Bu, kat\u0131 bir yap\u0131sal s\u0131n\u0131r de\u011fildir; zincir fiziksel olarak daha az di\u015fe oturur. Bu, d\u00fczg\u00fcnl\u00fck ve yorulma \u00f6mr\u00fc s\u0131n\u0131r\u0131d\u0131r. Hassas uygulamalar (servo indeksleme, \u00f6l\u00e7\u00fcm tahrikleri) i\u00e7in, s\u00fcr\u00fcc\u00fcde minimum 21 di\u015f, pratik m\u00fchendislik taban\u0131d\u0131r.<\/p>\n

Pratik kural:<\/strong> Her di\u015f say\u0131s\u0131 hesaplamas\u0131na N1 = 17 (veya hassasiyet i\u00e7in 19 veya 21) ile ba\u015flay\u0131n. Oran elde etmek i\u00e7in asla N1'i azaltmay\u0131n; bunun yerine N2'yi ayarlay\u0131n.<\/div>\n<\/div>\n<\/div>\n

<\/p>\n

\n
\n
2<\/div>\n
Maksimum tahrik edilen di\u015fli \u00e7ap\u0131: montaj aral\u0131\u011f\u0131<\/div>\n<\/div>\n
\n

Tahrik edilen di\u015flinin ad\u0131m dairesi \u00e7ap\u0131 (PD) \u015fu \u015fekilde hesaplan\u0131r: PD = p \/ sin(180\u00b0 \/ N2). D\u0131\u015f \u00e7ap (OD) yakla\u015f\u0131k olarak \u015f\u00f6yledir: OD \u2248 PD + 0,625p (standart di\u015f y\u00fcksekli\u011fi yakla\u015f\u0131m\u0131 kullan\u0131larak). Bu OD, biti\u015fik bile\u015fenlere, koruyuculara ve g\u00f6vdelere olan t\u00fcm bo\u015fluklar dahil olmak \u00fczere mevcut montaj zarf\u0131na s\u0131\u011fmal\u0131d\u0131r. Y\u00fcksek red\u00fcksiyon oranlar\u0131 i\u00e7in, tahrik edilen di\u015flinin OD'si genellikle ba\u011flay\u0131c\u0131 k\u0131s\u0131tlamad\u0131r - oran de\u011fil.<\/p>\n

\n\n\n\n\n\n\n\n\n\n\n
Oran<\/th>\nN1=17, N2=<\/th>\nPD #60 (mm)<\/th>\nOD #60 (mm)<\/th>\nPD #40 (mm)<\/th>\nOD #40 (mm)<\/th>\n<\/tr>\n<\/thead>\n
2:1<\/td>\n34<\/td>\n206.8<\/td>\n218.7<\/td>\n138.0<\/td>\n146.0<\/td>\n<\/tr>\n
3:1<\/td>\n51<\/td>\n309.7<\/td>\n321.6<\/td>\n206.8<\/td>\n214.7<\/td>\n<\/tr>\n
4:1<\/td>\n68<\/td>\n412.9<\/td>\n424.8<\/td>\n275.6<\/td>\n283.5<\/td>\n<\/tr>\n
5:1<\/td>\n85<\/td>\n516.0<\/td>\n527.9<\/td>\n344.4<\/td>\n352.3<\/td>\n<\/tr>\n
6:1<\/td>\n102<\/td>\n619.4<\/td>\n631.3<\/td>\n413.5<\/td>\n421.4<\/td>\n<\/tr>\n
7:1<\/td>\n119<\/td>\n722.8<\/td>\n734.7<\/td>\n482.3<\/td>\n490.2<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n<\/div>\n

<\/p>\n

\n
\n
3<\/div>\n
S\u00fcr\u00fcc\u00fcdeki minimum sarma a\u00e7\u0131s\u0131: 120\u00b0 (6 di\u015f temas halinde)<\/div>\n<\/div>\n
\n

ANSI B29.1 standard\u0131, yay\u0131nlanan g\u00fc\u00e7 de\u011ferlerinin ge\u00e7erli olmas\u0131 i\u00e7in k\u00fc\u00e7\u00fck (tahrik) di\u015flide minimum 120\u00b0'lik bir sar\u0131m a\u00e7\u0131s\u0131 gerektirir. 120\u00b0'nin alt\u0131nda, ayn\u0131 anda y\u00fcke temas eden di\u015f say\u0131s\u0131 3-4'\u00fcn alt\u0131na d\u00fc\u015fer ve di\u015f ba\u015f\u0131na y\u00fck, zincir \u00e7ekme kapasitesinin d\u00fc\u015f\u00fcr\u00fclmesi gereken noktaya kadar artar. Sar\u0131m a\u00e7\u0131s\u0131, orana ve merkez mesafesine ba\u011fl\u0131d\u0131r: daha y\u00fcksek oranlar ve daha k\u0131sa merkez mesafeleri, sar\u0131m a\u00e7\u0131s\u0131n\u0131 azalt\u0131r. Form\u00fcl \u015f\u00f6yledir: \u03b8 = 180\u00b0 \u2212 2 \u00d7 arcsin((PD2 \u2212 PD1) \/ (2C)), burada PD2 ve PD1, tahrik edilen ve tahrik di\u015flilerinin ad\u0131m dairesi \u00e7aplar\u0131 ve C, merkez mesafesidir. \u00c7o\u011fu pratik merkez mesafesi i\u00e7in (zincir ad\u0131m\u0131n\u0131n 30-50 kat\u0131), 5:1'e kadar olan oranlar, d\u00fczeltme yap\u0131lmadan minimum 120\u00b0'lik sar\u0131m\u0131 korur.<\/p>\n<\/div>\n<\/div>\n

<\/p>\n

\n
\n
4<\/div>\n
Maksimum tek kademeli oran: 7:1 (ANSI \u00f6nerisi)<\/div>\n<\/div>\n
\n

ANSI B29.1, maksimum tek kademeli oran\u0131 7:1 olarak \u00f6nermektedir. Bu oran\u0131n \u00fczerinde, 120\u00b0 sar\u0131m a\u00e7\u0131s\u0131n\u0131 korumak i\u00e7in ya pratik olmayan uzun bir merkez mesafesi ya da gev\u015fek tarafta bir zincir gerdiricisi gereklidir. Daha pratik olarak, tahrik edilen di\u015fli \u00e7ok b\u00fcy\u00fck olur (yukar\u0131daki K\u0131s\u0131tlama 2'ye bak\u0131n) ve uzun gev\u015fek taraftaki zincir sarkmas\u0131 aktif gerdirme gerektirir. 7:1'in \u00fczerindeki oranlar, iki kademeli bir tahrikle (ara \u015faft \u00fczerinde seri halde iki di\u015fli \u00e7ifti) elde edilmelidir. Tek kademeli 49:1 tahrikin neredeyse hi\u00e7bir zaman kullan\u0131\u015fl\u0131 zincir aral\u0131\u011f\u0131nda pratik olmad\u0131\u011f\u0131 durumlarda, 49:1'e (7:1 \u00d7 7:1) ula\u015fan iki kademeli bir tahrik fiziksel olarak m\u00fcmk\u00fcnd\u00fcr.<\/p>\n<\/div>\n<\/div>\n

<\/p>\n

\n
\n
5<\/div>\n
Avc\u0131 di\u015fi prensibi: N1 ve N2 aras\u0131nda ortak fakt\u00f6rlerden ka\u00e7\u0131n\u0131n.<\/div>\n<\/div>\n
\n

Di\u015f say\u0131lar\u0131 N1 ve N2'nin ortak b\u00f6leni 1'den b\u00fcy\u00fck oldu\u011funda, her devirde ayn\u0131 makara ayn\u0131 di\u015fli \u00e7ark di\u015fine temas eder; a\u015f\u0131nma, t\u00fcm di\u015flere e\u015fit olarak da\u011f\u0131lmak yerine, di\u015flerin bir alt k\u00fcmesinde yo\u011funla\u015f\u0131r. 17 di\u015fli tahrik eden ve 34 di\u015fli tahrik edilen bir di\u015fli \u00e7ark i\u00e7in (oran 2:1), her makara 34 tahrik edilen di\u015fin ayn\u0131 17'sine temas eder; alternatif 17 tahrik edilen di\u015f asla y\u00fcklenmez. 17 di\u015fli tahrik eden ve 35 di\u015fli tahrik edilen (tam say\u0131 olmayan oran) kullanmak, her tahrik edilen di\u015fin zaman i\u00e7inde temas halinde olmas\u0131n\u0131 sa\u011flar. Kural: N1 ve N2'nin m\u00fcmk\u00fcn olan her yerde en b\u00fcy\u00fck ortak b\u00f6leninin (EBOB) 1 olmas\u0131n\u0131 sa\u011flay\u0131n.<\/p>\n<\/div>\n<\/div>\n

<\/p>\n

Uygulama \u00d6rne\u011fi 1: Paketleme Konvey\u00f6r\u00fc i\u00e7in H\u0131z Azaltma Tahrik Sistemi<\/h2>\n

\u00d6zellikler:<\/strong> Motor \u00e7\u0131k\u0131\u015f mili 1450 RPM'de. Gerekli konvey\u00f6r mili h\u0131z\u0131: 96 RPM. Tahrik edilen di\u015fli \u00e7ark i\u00e7in mevcut montaj aral\u0131\u011f\u0131: maksimum 280 mm d\u0131\u015f \u00e7ap. Zincir ad\u0131m\u0131: ANSI #50 (15,875 mm). Uygulama: paketleme hatt\u0131 indeksleyici - sorunsuz \u00e7al\u0131\u015fma gereklidir.<\/p>\n

\n
Ad\u0131m ad\u0131m \u00e7\u00f6z\u00fcm<\/div>\n
    \n
  1. Gerekli oran:<\/strong> i = n1 \/ n2 = 1450 \/ 96 = 15.1:1<\/strong>Bu, 7:1 tek kademeli maksimum oran\u0131 a\u015f\u0131yor \u2192 iki kademeli s\u00fcr\u00fcc\u00fc gerekiyor.<\/li>\n
  2. Oran\u0131 iki a\u015famaya ay\u0131r\u0131n:<\/strong> \u221a15,1 \u2248 3,89. \u0130ki benzer a\u015fama hedefleyin. A\u015fama 1 oran\u0131 \u2248 3,9:1. A\u015fama 2 oran\u0131 \u2248 3,87:1 (3,9 \u00d7 3,87 = 15,09 \u2014 yeterince yak\u0131n). Ula\u015f\u0131labilir di\u015f say\u0131s\u0131na yuvarlay\u0131n.<\/li>\n
  3. 1. A\u015fama di\u015f say\u0131s\u0131:<\/strong> N1 = 19T ile ba\u015flay\u0131n (hassas uygulama). N2 = 19 \u00d7 3,9 = 74,1 \u2192 73T'ye yuvarlay\u0131n (tek say\u0131 - avc\u0131 di\u015fi kural\u0131n\u0131 kar\u015f\u0131lar, GCD(19,73) = 1). Ger\u00e7ek oran a\u015famas\u0131 1: 73\/19 = 3,842.<\/li>\n
  4. 2. evre di\u015f say\u0131s\u0131:<\/strong> Ara mil h\u0131z\u0131 = 1450 \/ 3,842 = 377 RPM. 96 RPM'ye ula\u015fmak i\u00e7in gerekli 2. kademe oran\u0131: 377 \/ 96 = 3,927. N3 = 19T ile ba\u015flay\u0131n. N4 = 19 \u00d7 3,927 = 74,6 \u2192 75T (GCD(19,75) = 1). Ger\u00e7ek 2. kademe oran\u0131: 75\/19 = 3,947. Son \u00e7\u0131k\u0131\u015f: 1450 \/ (3,842 \u00d7 3,947) = 95,6 RPM \u2248 96 RPM \u2713<\/strong><\/li>\n
  5. Tahrik edilen di\u015fli \u00e7ark\u0131n d\u0131\u015f \u00e7ap\u0131n\u0131, belirtilen de\u011ferlerle kar\u015f\u0131la\u015ft\u0131r\u0131n:<\/strong> En b\u00fcy\u00fck di\u015fli \u00e7ark #50 hatveli 75T'dir. PD = 15,875 \/ sin(180\u00b0\/75) = 15,875 \/ sin(2,4\u00b0) = 15,875 \/ 0,04188 = 379,1 mm. OD \u2248 379,1 + (0,625 \u00d7 15,875) = 379,1 + 9,9 = 389 mm<\/strong>Bu, 280 mm'lik s\u0131n\u0131r\u0131 a\u015f\u0131yor; ya ses aral\u0131\u011f\u0131n\u0131 azaltmal\u0131 ya da kademe say\u0131s\u0131n\u0131 art\u0131rmal\u0131y\u0131z.<\/li>\n
  6. \u00c7\u00f6z\u00fcn\u00fcrl\u00fck:<\/strong> #40 zincirine (12,70 mm ad\u0131m) d\u00fc\u015f\u00fcr\u00fcn. #40 ad\u0131m\u0131nda 75T: PD = 12,70 \/ sin(2,4\u00b0) = 303,3 mm. OD \u2248 303,3 + 7,9 = 311 mm<\/strong>Hala 31 mm fazla. 70T'ye d\u00fc\u015f\u00fcr\u00fcn: PD = 12,70 \/ sin(2,57\u00b0) = 283,2 mm. OD \u2248 283,2 + 7,9 = 291 mm<\/strong>280 mm maksimum zarf dahilinde. Yeni kademe 2 oran\u0131: 70\/19 = 3,684. Son h\u0131z: 1450 \/ (3,842 \u00d7 3,684) = 102,4 RPM<\/strong>Bu uygulama i\u00e7in uygundur (spesifikasyon tolerans\u0131 \u00b110%). \u2713<\/li>\n<\/ol>\n<\/div>\n
    Beklenenin aksine: zincir ad\u0131m\u0131n\u0131 azaltmak, ayn\u0131 di\u015fli d\u0131\u015f \u00e7ap\u0131nda daha y\u00fcksek di\u015f say\u0131s\u0131na olanak tan\u0131r; bu da montaj alan\u0131na uyarken daha ak\u0131c\u0131 bir s\u00fcr\u00fc\u015f sa\u011flar.<\/strong> #50'den #40'a ge\u00e7i\u015f, ayn\u0131 di\u015f say\u0131s\u0131nda di\u015fli \u00e7ark\u0131n d\u0131\u015f \u00e7ap\u0131n\u0131 389 mm'den 311 mm'ye d\u00fc\u015f\u00fcrd\u00fc. Bu daha k\u00fc\u00e7\u00fck ad\u0131m, tahrik di\u015f say\u0131s\u0131n\u0131n g\u00f6receli avantaj\u0131n\u0131 da art\u0131r\u0131r; 19T'de, #40 zinciri, fiziksel kiri\u015f uzunlu\u011fu (ve dolay\u0131s\u0131yla ba\u011flant\u0131 ba\u015f\u0131na a\u00e7\u0131sal varyasyon) daha k\u00fc\u00e7\u00fck oldu\u011fu i\u00e7in #50 zincirine g\u00f6re daha az \u00e7okgen etkisi h\u0131z varyasyonuna sahiptir. K\u0131s\u0131tl\u0131 bir zarfta daha k\u00fc\u00e7\u00fck ad\u0131ml\u0131, daha y\u00fcksek di\u015f say\u0131s\u0131na sahip \u00e7\u00f6z\u00fcm, genellikle daha b\u00fcy\u00fck ad\u0131ml\u0131 \u00e7\u00f6z\u00fcme g\u00f6re hem daha d\u00fczg\u00fcn hem de daha k\u00fc\u00e7\u00fckt\u00fcr.<\/div>\n

    <\/p>\n

    \u00c7al\u0131\u015f\u0131lm\u0131\u015f \u00d6rnek 2: Jenerat\u00f6r i\u00e7in H\u0131z Art\u0131rma Tahrik Sistemi (A\u015f\u0131r\u0131 H\u0131z)<\/h2>\n

    \u00d6zellikler:<\/strong> Dizel motorun PTO devri 1.000 RPM. Jenerat\u00f6r 1.800 RPM giri\u015f devri gerektirir. Zincir ad\u0131m\u0131: ANSI #80 (25,4 mm) \u2014 jenerat\u00f6r \u00fcreticisi taraf\u0131ndan zaten belirtilmi\u015ftir. Do\u011fru di\u015fli say\u0131s\u0131n\u0131 bulun.<\/p>\n

    \n
    \n
    \n
    i = n_engine \/ n_gen = 1000\/1800 = 0.556
    \nN2\/N1 = 0,556 \u2192 N1 > N2 (h\u0131z art\u0131\u015f\u0131)
    \nN2 = tahrik edilen (jenerat\u00f6r) = daha k\u00fc\u00e7\u00fck di\u015fli
    \nN1 = tahrik (motor) = daha b\u00fcy\u00fck di\u015fli<\/div>\n<\/div>\n

    A\u015f\u0131r\u0131 h\u0131z konfig\u00fcrasyonunda, tahrik eden di\u015fli daha b\u00fcy\u00fck olan di\u015flidir. Tahrik edilen di\u015flide (daha k\u00fc\u00e7\u00fck olan) en az 17T ile ba\u015flay\u0131n: N2 = 17T. N1 = N2 \/ i = 17 \/ 0,556 = 30,6 \u2192 31T'ye yuvarlay\u0131n. Ger\u00e7ek oran: 17\/31 = 0,548. Ger\u00e7ek jenerat\u00f6r h\u0131z\u0131: 1000 \/ 0,548 = 1.825 devir\/dakika<\/strong> \u2014 hedefin 1.4%'si i\u00e7inde. GCD(31, 17) = 1 \u2713 (avc\u0131 di\u015fi tatmin oldu).<\/p>\n

    Zarf kontrol\u00fc:<\/strong> #80 hatveli tahrik di\u015flisi (17T): PD = 25,4 \/ sin(10,59\u00b0) = 138,1 mm. OD \u2248 138,1 + 15,9 = 154 mm. Tahrik di\u015flisi (31T): PD = 25,4 \/ sin(5,81\u00b0) = 250,7 mm. OD \u2248 250,7 + 15,9 = 267 mm. Her ikisi de motor-jenerat\u00f6r ba\u011flant\u0131s\u0131 i\u00e7in tipik montaj s\u0131n\u0131rlar\u0131 dahilindedir.<\/p>\n<\/div>\n

    \"\"<\/p>\n

    Zincir ve di\u015fli tahrik sistemi \u2014 do\u011fru di\u015f say\u0131s\u0131n\u0131n hesaplanmas\u0131, zincir tahrik geometrisi k\u0131s\u0131tlamalar\u0131n\u0131 korurken gerekli h\u0131z oran\u0131n\u0131 sa\u011flar.<\/p>\n<\/div>\n<\/div>\n

    <\/p>\n

    S\u0131k Kullan\u0131lan Oranlar \u0130\u00e7in H\u0131zl\u0131 Referans Di\u015f Say\u0131s\u0131 Kombinasyonlar\u0131<\/h2>\n

    En s\u0131k belirtilen oranlar i\u00e7in, a\u015fa\u011f\u0131daki tabloda be\u015f k\u0131s\u0131tlaman\u0131n t\u00fcm\u00fcn\u00fc kar\u015f\u0131layan \u00f6nceden hesaplanm\u0131\u015f di\u015f say\u0131s\u0131 \u00e7iftleri verilmi\u015ftir: minimum 17T s\u00fcr\u00fcc\u00fc, GCD = 1, tek kademeli oran \u2264 7:1 ve tam say\u0131 oran\u0131 olmamas\u0131 (bu, di\u015f da\u011f\u0131l\u0131m\u0131nda sapmaya neden olur).<\/p>\n

    \n\n\n\n\n\n\n\n\n\n\n\n
    Gerekli Oran<\/th>\nN1 (s\u00fcr\u00fcc\u00fc)<\/th>\nN2 (s\u00fcr\u00fcc\u00fcl\u00fc)<\/th>\nGer\u00e7ek Oran<\/th>\nOran Hatas\u0131<\/th>\nGCD<\/th>\nPD (N2) #60'ta (mm)<\/th>\nNotlar<\/th>\n<\/tr>\n<\/thead>\n
    1.5:1<\/td>\n19<\/td>\n29<\/td>\n1.526<\/td>\n+1.7%<\/td>\n1 \u2713<\/td>\n174.3<\/td>\nKompakt; iyi p\u00fcr\u00fczs\u00fczl\u00fck<\/td>\n<\/tr>\n
    2:1<\/td>\n19<\/td>\n37<\/td>\n1.947<\/td>\n\u22122.6%<\/td>\n1 \u2713<\/td>\n224.5<\/td>\n19:38 tam do\u011fru ama EBOB=19 \u2014 bundan ka\u00e7\u0131n\u0131n<\/td>\n<\/tr>\n
    2.5:1<\/td>\n17<\/td>\n43<\/td>\n2.529<\/td>\n+1.2%<\/td>\n1 \u2713<\/td>\n261.2<\/td>\n<\/td>\n<\/tr>\n
    3:1<\/td>\n19<\/td>\n57<\/td>\n3.000<\/td>\n0%<\/td>\n19 \u2717<\/td>\n346.2<\/td>\n19:58 (EBOB=1) veya 17:51 (EBOB=17!) kullan\u0131n \u2192 bunun yerine 17:53 kullan\u0131n<\/td>\n<\/tr>\n
    3:1 (d\u00fczeltilmi\u015f)<\/td>\n17<\/td>\n53<\/td>\n3.118<\/td>\n+3.9%<\/td>\n1 \u2713<\/td>\n321.8<\/td>\n\u00b15% h\u0131z tolerans\u0131 kabul edilebilir.<\/td>\n<\/tr>\n
    4:1<\/td>\n19<\/td>\n75<\/td>\n3.947<\/td>\n\u22121.3%<\/td>\n1 \u2713<\/td>\n455.5<\/td>\n19:76 tam olarak do\u011fru ancak EBOB=19 \u2014 ka\u00e7\u0131n\u0131n<\/td>\n<\/tr>\n
    5:1<\/td>\n19<\/td>\n97<\/td>\n5.105<\/td>\n+2.1%<\/td>\n1 \u2713<\/td>\n589.2<\/td>\nB\u00fcy\u00fck tahrik di\u015flisi \u2014 d\u0131\u015f \u00e7ap\u0131 kontrol edin<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

    <\/p>\n

    \u0130ki A\u015famal\u0131 Zincir Tahrik Sistemlerinin Tasar\u0131m\u0131: Ara Mil ve A\u015fama Oran\u0131 Ayr\u0131m\u0131<\/h2>\n

    Gerekli oran 7:1'i a\u015ft\u0131\u011f\u0131nda veya tahrik edilen di\u015flinin d\u0131\u015f \u00e7ap\u0131 tek kademeli montaj s\u0131n\u0131rlar\u0131n\u0131 a\u015ft\u0131\u011f\u0131nda, ara \u015faftl\u0131 iki kademeli bir tahrik sistemi standart \u00e7\u00f6z\u00fcmd\u00fcr. Ara \u015faft, hem tahrik edilen di\u015fliyi (1. kademeden g\u00fc\u00e7 alan) hem de tahrik eden di\u015fliyi (2. kademeye g\u00fc\u00e7 veren) ta\u015f\u0131r. \u0130ki kademe oran\u0131 \u00e7arp\u0131larak toplam oran elde edilir: i_toplam = i_kademe1 \u00d7 i_kademe2.<\/p>\n

    \u0130ki kademeli bir d\u00fczenlemede en iyi genel tahrik performans\u0131 i\u00e7in, kademe oranlar\u0131 yakla\u015f\u0131k olarak e\u015fit olmal\u0131d\u0131r; bu, sistemdeki en b\u00fcy\u00fck di\u015flinin boyutunu en aza indirir. E\u015fit olmayan bir kademe da\u011f\u0131l\u0131m\u0131 (\u00f6rne\u011fin, toplam 15:1 i\u00e7in 3:1 ve 5:1), e\u015fit bir da\u011f\u0131l\u0131mdan (\u00f6rne\u011fin, ayn\u0131 15:1 i\u00e7in 3,87:1 ve 3,87:1) daha b\u00fcy\u00fck bir maksimum di\u015fli \u00fcretir. E\u015fit kademe oranlar\u0131 ayr\u0131ca, iletilen g\u00fc\u00e7 ayn\u0131 oldu\u011funda her iki kademede de e\u015fit zincir gerilimleri \u00fcretir, bu da zincir boyutland\u0131rmay\u0131 basitle\u015ftirir.<\/p>\n

    Ara mil yataklar\u0131, mile etki eden her iki zincir tahrikinden kaynaklanan birle\u015fik radyal y\u00fcklere g\u00f6re boyutland\u0131r\u0131lmal\u0131d\u0131r. \u0130ki kademeli bir tahrikte, 1. ve 2. kademeden gelen gergin taraf gerilimleri, zincir \u00e7al\u0131\u015fma geometrisi taraf\u0131ndan belirlenen y\u00f6nlerde etki eder; e\u011fer her iki gergin taraf da ara mili z\u0131t y\u00f6nlerde \u00e7ekiyorsa, yatak y\u00fckleri k\u0131smen birbirini g\u00f6t\u00fcr\u00fcr. E\u011fer her ikisi de ayn\u0131 y\u00f6nde \u00e7ekiyorsa, y\u00fckler toplan\u0131r. Ara mil yataklar\u0131n\u0131 belirlemeden \u00f6nce her zaman zincir geometrisi diyagram\u0131n\u0131 \u00e7izin ve sonu\u00e7ta ortaya \u00e7\u0131kan mil y\u00fck vekt\u00f6r\u00fcn\u00fc hesaplay\u0131n. Bu ad\u0131m pratikte s\u0131kl\u0131kla atlan\u0131r ve bu da zincirlerden herhangi biri ar\u0131zalanmadan \u00f6nce yetersiz boyutland\u0131r\u0131lm\u0131\u015f ara mil yataklar\u0131na yol a\u00e7ar.<\/p>\n

    \"di\u015fli<\/p>\n

    Di\u015f say\u0131s\u0131 hesaplamas\u0131n\u0131n kritik tasar\u0131m ad\u0131m\u0131 oldu\u011fu yerlerde<\/h2>\n

    Tar\u0131m makinelerinin yenilenmesi.<\/strong> Eski makinelerde, dok\u00fcmantasyonun kayboldu\u011fu durumlarda hasarl\u0131 veya a\u015f\u0131nm\u0131\u015f di\u015flileri de\u011fi\u015ftirirken, do\u011fru di\u015f say\u0131s\u0131n\u0131 teyit etmenin tek yolu, orijinal di\u015fliyi (varsa) \u00f6l\u00e7mek, \u00f6l\u00e7\u00fclen di\u015f say\u0131lar\u0131ndan h\u0131z oran\u0131n\u0131 hesaplamak ve makinenin \u00e7al\u0131\u015fma parametreleriyle kar\u015f\u0131la\u015ft\u0131rmakt\u0131r. Yanl\u0131\u015f di\u015f say\u0131lar\u0131, besleme h\u0131zlar\u0131n\u0131, konvey\u00f6r h\u0131zlar\u0131n\u0131 ve harmanlama h\u0131zlar\u0131n\u0131 de\u011fi\u015ftirerek, do\u011frudan mekanik ar\u0131zaya neden olmaktan ziyade, \u00fcr\u00fcn kalitesini ve hasat verimlili\u011fini etkiler; bu da hatan\u0131n te\u015fhisini zorla\u015ft\u0131r\u0131r. tar\u0131msal di\u015fli \u00e7ark de\u011fi\u015fimleri<\/a> Belgeler eksikse, orijinal di\u015fli \u00e7ark di\u015f say\u0131s\u0131n\u0131 ve giri\u015f ve \u00e7\u0131k\u0131\u015f mili devir say\u0131s\u0131n\u0131 g\u00f6nderin, m\u00fchendislerimiz do\u011fru oran\u0131 onaylayabilir.<\/p>\n

    Konvey\u00f6r h\u0131z\u0131n\u0131n de\u011fi\u015ftirilmesi.<\/strong> Konvey\u00f6r hatt\u0131 h\u0131z\u0131n\u0131n de\u011fi\u015ftirilmesi gerekti\u011finde (genellikle \u00fcretim verimlili\u011fini art\u0131rma amac\u0131yla), zincir tahrik sisteminde en ekonomik yakla\u015f\u0131m, tahrik edilen di\u015fli \u00e7ark\u0131n di\u015f say\u0131s\u0131n\u0131 de\u011fi\u015ftirmektir. Mevcut #60 zincir tahrik sisteminde, 19T tahrik di\u015flisi ile 45T'den 40T'ye tahrik di\u015flisi de\u011fi\u015ftirilmesi, konvey\u00f6r h\u0131z\u0131n\u0131 orijinal 100%'den 45\/40 = 112,5%'ye \u00e7\u0131kar\u0131r. Zincir ad\u0131m\u0131 ve genel sistem de\u011fi\u015fmeden kal\u0131r. standart \u00e7apl\u0131 di\u015fliler, yayg\u0131n zincir aral\u0131klar\u0131nda<\/a>Tek bir di\u015f say\u0131s\u0131ndaki de\u011fi\u015fiklik genellikle planl\u0131 bir bak\u0131m penceresi i\u00e7inde ve minimum kesinti s\u00fcresiyle uygulanabilir.<\/p>\n

    \"di\u015fli<\/p>\n

    \u015eanz\u0131man baypas veya oran de\u011fi\u015fikli\u011fi.<\/strong> Baz\u0131 end\u00fcstriyel tahrik sistemlerinde, di\u015fli kutusu hasar g\u00f6rm\u00fc\u015f veya farkl\u0131 nominal h\u0131za sahip yeni bir motor tak\u0131l\u0131yor olabilir. Di\u015fli kutusunu de\u011fi\u015ftirmek yerine, yeni bir zincir tahrik oran\u0131 bazen gerekli \u00e7\u0131k\u0131\u015f h\u0131z\u0131n\u0131 do\u011frudan sa\u011flayabilir. \u00d6rne\u011fin, bir konvey\u00f6r \u00fczerindeki 4:1 oranl\u0131 bir di\u015fli kutusunun 4:1 oranl\u0131 do\u011frudan zincir tahrik sistemiyle de\u011fi\u015ftirilmesi, di\u015fli kutusu bak\u0131m gereksinimini tamamen ortadan kald\u0131r\u0131r. Bu, ancak zincir tahrik sisteminin kapasitesi ve zincir boyutu tam nominal torku kar\u015f\u0131layabiliyorsa m\u00fcmk\u00fcnd\u00fcr; bu da bu makalede \u00f6zetlenen be\u015f k\u0131s\u0131tlaman\u0131n dikkate al\u0131nmas\u0131n\u0131 gerektirir.<\/p>\n

    <\/p>\n

    S\u0131k\u00e7a Sorulan Sorular<\/h2>\n
    \nGer\u00e7ek oran\u0131n hedef orana ne kadar yak\u0131n olmas\u0131 gerekiyor? Kabul edilebilir tolerans nedir?<\/summary>\n
    Kabul edilebilir oran tolerans\u0131 tamamen uygulama gereksinimine ba\u011fl\u0131d\u0131r. H\u0131z\u0131n verimi etkiledi\u011fi konvey\u00f6r tahriklerinde: \u00b15% genellikle kabul edilebilir; zincir tahrik oran\u0131 konvey\u00f6r h\u0131z\u0131n\u0131 belirler ve proses m\u00fchendisli\u011fi genellikle bu varyasyona tolerans g\u00f6sterebilir. Senkronize makinelerle ba\u011flant\u0131l\u0131 tahriklerde (zincir tahrik oran\u0131n\u0131n mekanik zamanlama ili\u015fkisine uymas\u0131 gerekti\u011fi durumlarda): \u00b11% veya daha az\u0131; di\u015f say\u0131s\u0131, teorik orana \u00e7ok yak\u0131n bir yakla\u015f\u0131m elde etmek i\u00e7in se\u00e7ilmelidir. \u00c7\u0131k\u0131\u015f mili h\u0131z\u0131n\u0131n bir h\u0131z kontrol sistemine (VFD, servo) beslendi\u011fi tahriklerde: \u00b110% kabul edilebilir \u00e7\u00fcnk\u00fc h\u0131z kontrol\u00f6r\u00fc oran hatas\u0131n\u0131 telafi eder. Di\u015f say\u0131s\u0131 kombinasyonuna karar vermeden \u00f6nce, tahrik edilen makinenin h\u0131z tolerans\u0131n\u0131 daima do\u011frulay\u0131n.<\/div>\n<\/details>\n
    \nHer iki di\u015fli \u00e7arkta da daha fazla di\u015f kullanmak (ayn\u0131 oran, daha fazla di\u015f say\u0131s\u0131) tahrik performans\u0131n\u0131 art\u0131r\u0131r m\u0131 yoksa azalt\u0131r m\u0131?<\/summary>\n
    Ayn\u0131 oran\u0131 korurken her iki di\u015flinin di\u015f say\u0131s\u0131n\u0131 art\u0131rmak, tahrik performans\u0131n\u0131 \u00f6l\u00e7\u00fclebilir \u00e7e\u015fitli \u015fekillerde iyile\u015ftirir. Tahrik di\u015flisindeki daha fazla di\u015f, \u00e7okgen etkisi h\u0131z varyasyonunu azalt\u0131r. Her iki di\u015flideki daha fazla di\u015f, ad\u0131m dairesi \u00e7aplar\u0131n\u0131 art\u0131r\u0131r; bu da ayn\u0131 \u015faft devri i\u00e7in zincir h\u0131z\u0131n\u0131 art\u0131r\u0131r - zincir h\u0131z\u0131ndaki art\u0131\u015f, etkili g\u00fc\u00e7 aktar\u0131m kapasitesini art\u0131r\u0131r (\u00e7\u00fcnk\u00fc g\u00fc\u00e7 = zincir \u00e7ekme kuvveti \u00d7 h\u0131z). Her iki di\u015flideki daha fazla di\u015f ayr\u0131ca, her bir di\u015fliyle ayn\u0131 anda temas eden ba\u011flant\u0131 say\u0131s\u0131n\u0131 art\u0131rarak gerilim y\u00fck\u00fcn\u00fc daha fazla di\u015fe da\u011f\u0131t\u0131r ve di\u015f ba\u015f\u0131na temas gerilimini azalt\u0131r. Di\u015f say\u0131s\u0131n\u0131 \"art\u0131rman\u0131n\" pratik s\u0131n\u0131rlar\u0131, ortaya \u00e7\u0131kan di\u015fli d\u0131\u015f \u00e7aplar\u0131 (montaj alan\u0131) ve daha b\u00fcy\u00fck di\u015flilerden kaynaklanan artan d\u00f6nme ataletidir (bu, y\u00fcksek ivmeli indeksleme tahriklerinde \u00f6nemlidir).<\/div>\n<\/details>\n
    \nDi\u015f say\u0131s\u0131n\u0131 do\u011frulad\u0131ktan sonra zincir uzunlu\u011funu ba\u011flant\u0131 say\u0131s\u0131 olarak nas\u0131l hesaplar\u0131m?<\/summary>\n
    Ba\u011flant\u0131 say\u0131s\u0131 cinsinden zincir uzunlu\u011fu: L = (2C\/p) + (N1 + N2)\/2 + ((N2 \u2212 N1)\u00b2 \u00d7 p) \/ (4\u03c0\u00b2 \u00d7 C), burada C, mm cinsinden merkez mesafesi, p, mm cinsinden zincir ad\u0131m\u0131, N1, tahrik eden di\u015f say\u0131s\u0131 ve N2, tahrik edilen di\u015f say\u0131s\u0131d\u0131r. Sonu\u00e7, \u00e7ift bir tam say\u0131ya yuvarlanmal\u0131d\u0131r (ofset yar\u0131m ba\u011flant\u0131 yerine standart bir ba\u011flant\u0131 sa\u011flamak i\u00e7in). Daha sonra, yuvarlanm\u0131\u015f ba\u011flant\u0131 say\u0131s\u0131ndan ger\u00e7ek merkez mesafesini \u015fu form\u00fclle tersine hesaplay\u0131n: C = (p\/4) \u00d7 {(L \u2212 (N1+N2)\/2) + \u221a[(L \u2212 (N1+N2)\/2)\u00b2 \u2212 8((N2\u2212N1)\/2\u03c0)\u00b2]}. Bu, montajda kullan\u0131lacak nihai merkez mesafesini verir - genellikle gerdirme mekanizmas\u0131n\u0131n \u00e7ekme aral\u0131\u011f\u0131na g\u00f6re ayarlanm\u0131\u015f, orijinal tasar\u0131m de\u011ferinin birka\u00e7 milimetre i\u00e7inde.<\/div>\n<\/details>\n
    \nZincir tahrik sistemi, avlanma di\u015fi prensibini ihlal etmeden tam say\u0131 oran\u0131na ula\u015fabilir mi?<\/summary>\n
    Evet \u2014 e\u011fer di\u015f say\u0131lar\u0131 aralar\u0131nda asal ise (EBOB = 1), oran tam say\u0131 yakla\u015f\u0131m\u0131 olsa bile. \u00d6rne\u011fin, 17:34 tam olarak 2:1 oran verir ancak EBOB(17,34) = 17 \u2014 avlanan di\u015f prensibi ihlal edilir. Bununla birlikte, 19:38 de EBOB(19,38) = 19 ile 2:1 oran verir. 2:1 oran i\u00e7in \u00e7\u00f6z\u00fcm, N2 = 2\u00d7N1 olan herhangi bir kombinasyon yerine 17:35'i (oran 2,06:1, EBOB=1) kullanmakt\u0131r. Avlanan di\u015f prensibi, tam say\u0131 oran\u0131na ula\u015fmaktan ziyade uzun \u00f6m\u00fcrl\u00fc tahrik sistemleri i\u00e7in daha \u00f6nemlidir. Tam 2:1 veya 3:1 oran\u0131n\u0131n geometrik olarak gerekli oldu\u011fu senkronize mekanik tahrik sistemlerinde (\u00f6rne\u011fin, bir eksantrik mili zamanlama tahrik sistemi), EBOB k\u0131s\u0131tlamas\u0131n\u0131 kabul edin ve avlanan di\u015f da\u011f\u0131t\u0131m mekanizmas\u0131 yerine daha s\u0131k kontrol aral\u0131klar\u0131na g\u00fcvenin.<\/div>\n<\/details>\n

    <\/p>\n

    \n
    <\/div>\n
    \n
    N2 = N1 \u00d7 i \u2192 PD = p \/ sin(180\u00b0 \/ N) \u2192 OD \u2248 PD + 0.625p<\/div>\n

    Hesaplad\u0131\u011f\u0131n\u0131z di\u015f say\u0131s\u0131na g\u00f6re i\u015flenmi\u015f di\u015fli \u00e7arklara m\u0131 ihtiyac\u0131n\u0131z var?<\/h2>\n

    \u0130stenen oran\u0131, \u015faft h\u0131zlar\u0131n\u0131, mevcut \u00e7al\u0131\u015fma aral\u0131\u011f\u0131n\u0131 ve zincir ad\u0131m\u0131n\u0131 g\u00f6nderin; m\u00fchendislerimiz imalattan \u00f6nce di\u015f say\u0131s\u0131 kombinasyonunu be\u015f k\u0131s\u0131tlaman\u0131n t\u00fcm\u00fcne g\u00f6re do\u011frular ve delik i\u015fleme \u00f6zelliklerini onaylar.<\/p>\n

    \u00d6zel Delikli Di\u015fli \u00c7arklar\u0131n\u0131 \u0130nceleyin<\/a>
    \n    Hesaplamalar\u0131n\u0131z\u0131 inceleme i\u00e7in g\u00f6nderin.<\/a><\/div>\n<\/div>\n<\/div>\n<\/div>\n

    Edit\u00f6r: Cxm<\/p>\n<\/div>","protected":false},"excerpt":{"rendered":"

    i = N2 \/ N1 \u00a0\u2192\u00a0 n2 = n1 \u00d7 (N1 \/ N2) How to Calculate Sprocket Tooth Count for Any Speed Ratio Choosing sprocket tooth counts by working backwards from a required speed ratio, shaft speed, or torque output \u2014 and then checking those counts against the engineering constraints that determine whether the drive […]<\/p>","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_et_pb_use_builder":"","_et_pb_old_content":"","_et_gb_content_width":"","footnotes":""},"categories":[6634],"tags":[72,78,58],"class_list":["post-3335","post","type-post","status-publish","format-standard","hentry","category-chain-sprocket","tag-chain","tag-chain-sprocket","tag-sprocket"],"_links":{"self":[{"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/posts\/3335","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/comments?post=3335"}],"version-history":[{"count":2,"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/posts\/3335\/revisions"}],"predecessor-version":[{"id":3337,"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/posts\/3335\/revisions\/3337"}],"wp:attachment":[{"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/media?parent=3335"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/categories?post=3335"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/sprocket-chain.net\/tr\/wp-json\/wp\/v2\/tags?post=3335"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}